Online Math Tutor LLC

Discover the Path to Mathematical Mastery 
An Education That Counts

Online Math Tutor LLC

Search
Close this search box.

Convergence Test

Hexagon Integration Icon to access power series information on Online Math Tutor, LLC

Divergence Test

Convergence Test

Also known as the n-th term test should be the first test to consider before using more advanced techniques. Unfortunately, this test cannot determine convergence.

If \(\underset{n\to\infty}{\lim}a_n\neq0\) then \( \sum a_n \) is guaranteed to diverge

If \(\underset{n\to\infty}{\lim}a_n=0\) then the test is inconclusive use another test.
Hexagon Integration Icon to access power series information on Online Math Tutor, LLC

Geometric Series

Convergence Test

Usefull for computing sums whenever \(n\) always appears as an exponent. May require using properties of exponents to compute a sum.

\(\displaystyle\sum_{n=0}^{\infty}x^n=\frac{1}{1-x}\, \text{if}\, |x|\)<\(1\)

Otherwise if \(|x|\geq1\) then the series in question will diverge.
Hexagon Integration Icon to access power series information on Online Math Tutor, LLC

Telescopic Series

Convergence Test

The terms in these series can be recalibrated as \(b_n=a_n-a_{n+1}\).

To obtain this format, you may be required to manipulated the terms algebraically by using techniques such as partial fractions or properties of logarithms.

\( \sum_{n=0}^{\infty}a_n-a_{n+1}=a_0-\underset{n\to\infty}{\lim}a_n\)
Hexagon Integration Icon to access power series information on Online Math Tutor, LLC

Limit Comparison Test (LCT)

Convergence Test

Useful for analyzing rational functions. Let \(a_n,b_n\) be nonnegative sequences.

Compute \(\underset{n\to\infty}{\lim}\frac{a_n}{b_n}=L\)

If \(0\)<\(L\)<\(\infty\) then

\(\textstyle\sum a_n\) and \(\textstyle\sum b_n\) will mimic the same behavior, i.e. they both converge or they both diverge.

If \(L=0\) or \(L=\infty\) then it is recommended to consider using another test
Hexagon Integration Icon to access power series information on Online Math Tutor, LLC

Direct Comparison Test (DCT)

Convergence Test

Let \(a_n,b_n,c_n\) be a nonnegtive sequence such that \(c_n\)<\(a_n\)<\(b_n\) then \(\sum c_n\)<\(\sum a_n\)<\(\sum b_n\)
  • If \(\sum c_n\) diverges then so does \(\sum a_n\)
  • If \(\sum b_n\) converges then so does \(\sum a_n\)
  • If \(\sum b_n\) divergess no information is provided
  • If \(\sum c_n\) converges no information is provided
Hexagon Integration Icon to access power series information on Online Math Tutor, LLC

Integral Test

Convergence Test

Useful when transcendental functions are present such as \(\texttt{ln}(x)\). To apply this test you must first verify that the terms are positive and decreasing.

\(f(x)\) is a continuous extension of \(a_n\)

The improper integral \( \int_{k}^{\infty}f(x) dx \) and the infinite series \( \sum_{n=k}^{\infty}a_n\) will mimic the same behavior, i.e., they both converge or they both diverge.
Hexagon Integration Icon to access power series information on Online Math Tutor, LLC

p-Series

Convergence Test

These series are helpful for comparing the convergence of a given series, especially when using the LCT or the DCT.

\( \displaystyle\sum_{n=1}^{\infty}\frac{1}{n^p} =\small{\left\{\begin{array}{ll} \text{Converges}\\ p>1\\[8pt] \text{Diverges}\\ p\leq1 \end{array} \right.} \)
Hexagon Integration Icon to access power series information on Online Math Tutor, LLC

ln-series

Convergence Test

As with the p-series, these series help us to compare the convergence of a given series, especially when using the LCT or the DCT.

\( \displaystyle\sum_{n=2}^{\infty}\frac{1}{n\big(ln(n)\big)^p} =\small{\left\{\begin{array}{l} \text{Converges}\\ p>1\\[8pt] \text{Diverges}\\ p\leq1 \end{array} \right.} \)
Hexagon Integration Icon to access power series information on Online Math Tutor, LLC

Generalized Geometric Series

Convergence Test

Usefull for computing sums whenever \(n\) always appears as an exponent. May require using properties of exponents to compute a sum.

\(\displaystyle\sum_{n=k}^{\infty}x^n=\frac{x^k}{1-x}\, \text{if}\, |x|\)<\(1\)

Otherwise if \(|x|\geq1\) then the series in question will diverge.
Hexagon Integration Icon to access power series information on Online Math Tutor, LLC

Ratio Test

Convergence Test

The ratio test is an excellent test when exponentials or factorials are present. However, the Ratio Test always inclusive when analyzing a rational function.

\(\underset{n\to\infty}{\lim}\left|\frac{a_{n+1}}{a_n}\right|=L\)

  • \(L\)<\(1\) Series converges
  • \(L>\) Series diverges
  • \(L=1\) Test is inconclusive
Hexagon Integration Icon to access power series information on Online Math Tutor, LLC

Root Test

Convergence Test

The root test is an excellent choice when powers, expoentials, and factorials are present. This test has more 'kick' than the Ratio Test.

\(\underset{n\to\infty}{\lim}\sqrt[n]{|a_n|}=L\)

  • \(L\)<\(1\) Series converges
  • \(L>1\) Series diverges
  • \(L=1\) Test is inconclusive
Hexagon Integration Icon to access power series information on Online Math Tutor, LLC

k-Tier Telescopic Series

Convergence Test

A k-tier telescopic series is generalizationof the classical telescopic \(b_n=a_n-a_{n+1}\).

\( \displaystyle\sum_{n=0}^{\infty}a_n-a_{n+2}=\\ \quad a_0+a_1-2\underset{n\to\infty}{\lim}a_n\)

\(\displaystyle \sum_{n=0}^{\infty}a_n-a_{n+k}=\\ \quad a_0+\cdots+a_{k-1}-k\underset{n\to\infty}{\lim}a_n\)
Hexagon Integration Icon to access power series information on Online Math Tutor, LLC

Alternating Series Test

Convergence Test

Useful for analyzing alternating series \(\textstyle\sum(-1)^na_n\), \(a_n\geq0\).

CAUTION: This test does not show divergece

Begin by showing \(\underset{n\to\infty}{\lim}a_n=0\). Then, prove \(a_n\) is a decreasing sequence by either applying the definition directly or using the first derivative test.

[Note, checking a few examples NEVER proves a statement]
Hexagon Integration Icon to access power series information on Online Math Tutor, LLC

Alternating Series Test 2.0

Convergence Test

Another approach for determining the convergence of \(\sum(-1)^na_n\) involves using assessing the convergence of \(\sum |a_n|\)

If \(\sum|a_n|\) converges then the alternating series \(\sum(-1)^na_n\) will converge absolutely.
Hexagon Integration Icon to access power series information on Online Math Tutor, LLC

Conditional vs Absolute Convergence

Convergence Test

To classify the convergence of an alternating series as either absolutely convergent or conditional congerneget we note the following definitions.

If \(\sum(-1)^na_n\) and \(\sum a_n\) both converge then the alternating series converges absolutely,

If \(\sum(-1)^na_n\) converges but \(\sum a_n\) diverges then the alternating series converges conditionally.

Alternating Series Error Term

Convergence Flowchart